NEET 2016 · Class 12

Principles of Inheritance and Variation

A tall true breeding garden pea plant is crossed with a dwarf true breeding garden pea plant. When the F1 plants were selfed the resulting genotypes were in the ratio of

  1. (A)3 : 1 :: Tall : Dwarf
  2. (B)3 : 1 :: Dwarf : Tall
  3. (C)1 : 2 : 1 :: Tall homozygous : Tall heterozygous : Dwarf
  4. (D)1 : 2 : 1 :: Tall heterozygous : Tall homozygous : Dwarf

The NCERT line that answers it

Verbatim line

From the Punnett square it is easily seen that $1/4^{\text{th}}$ of the random fertilisations lead to **TT**, $1/2$ lead to **Tt** and $1/4^{\text{th}}$ to **tt**.

Chapter
Principles of Inheritance and Variation
Section
4.2 INHERITANCE OF ONE GENE

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How this line gives the answer

0, emb=1.0, combined=1.0). Verified: high — The span explicitly states the genotypic ratio of 1/4 TT, 1/2 Tt, and 1/4 tt, which directly corresponds to the 1:2:1 ratio of tall homozygous : tall heterozygous : dwarf in option C.

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